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This is about positive integers, 0 < a < b < c (and other variables that are integers)
Like everyone, I have sensed that Fermat's Last Theorem is true. It was in a rather geometrical way--when I saw the picture of the shells or nexus numbers that add up to form cubes:
The proof was somehow already there. Shell/nexus numbers, that definitively "grow" an xn value, are a grasp-able concept that does lead to a proof-by-contradiction for Fermat's famous statement, which is roughly:
Figure 1. For an + bn = cn, n must be 1 or 2 to have integer solutions; In fact, n > 2 cannot have integer solutions for a, b, and c.
Formulas for shells for each power level are visibly related to Pascal's Triangle as is established in the binomial theorem. The Powers' Pattern also shows a basis of formulas by very interesting depictions of accumulations.
Figure 2. The first several shell/nexus number formulas.
1 = "Shell" difference formula S1 for x^1 2k – 1 = "Shell" difference formula S2 for x^2 3k^2 – 3k + 1 = "Shell" difference formula S3 for x^3 4k^3 – 6k^2 + 4k – 1 = "Shell" difference formula S4 for x^4 5k^4 – 10k^3 + 10k^2 – 5k + 1 = "Shell" difference formula S5 for x^5 6k^5 – 15k^4 + 20k^3 – 15k^2 + 6k – 1 = "Shell" difference formula S6 for x^6 etc.
Importantly, within the very concept of nexus number rests the fact that "shells" add up to create any xn value including the an, bn and cn within Fermat's Last Theorem. If cn serves as the total value of two, summed, power-of-n values, then the larger of the two values only further completes the lesser value's initial run of shells. Importantly, due to the commutative law of addition, either of the two terms may occur firstly or secondly.
So, assuming integers, 0 < a < b < c and n > 0 and assuming an + bn = cn ...the commutative law of addition as well as the shell/nexus number nature of any integer raised to a power are the basis of Figure 3.
Figure 3. Diagrammed shells accumulate to a cn total. Either an or bn may occur firstly in shell/nexus number sets, due to the commutative law of addition. S-sub-n represents the specific formula that generates shell/nexus number values for the power of n. The large sigma symbols indicate the procedure: apply integer number or variables, from the value located at the symbol's bottom through the variable located at the top, to the S-sub-n formula; sum-total values to establish a bracket's value. Shells are 'counted' by variables located on the top brackets. a + x + u = c. a + x = b. The equation at the bottom depicts known and/or assumed values of bracketed shell sets. "x-shells-value" is equivalent to [bn value less an value]. Carets "^" are placed within terms to clearly reinforce that the variable of that term is raised by the power of n.
The model that is Figure 4 diagrams all possible accumulations of significant shell-sets comprising a cn value pictured in Figure 3.
Figure 4. List of possible accumulations of a, x and u amounts of shells. Results are listed every time a choice must occur.
Beginning with no choice: {0,0,0}: First choice--possible results: {a,0,0};{0,x,0};{0,0,u}: Second choice--possible results: {a,x,0};{a,0,u};{0,x,u}: Third result: {a,x,u}.
Six different paths may be taken to accumulate a + x + u = c number of shells that equal cn value.1
Most of the paths of Figure 4 depict (an + bn) or (bn + an) that equal cn. 2(an) + (bn - an) = cn OR 2(an-value) + (x-shells'-value) = cn is also depicted.
Three sets of shells--a, x and u sets--may be graphed as lengths each extending in one certain direction. Each direction should be traveled only once to culminate in c total shells. This is a special three-variable vector. Figure 5 is special because it depicts non-Pythagorean-Triangle-logic where x and y number of shell lengths are legs of triangles that SUM to an (apparent) hypotenuse that totals simply, x + y, as a resultant length. This is because shells (only) accumulate in number. The model of figure 5 forces a linear accumulation onto an apparently non-linear depiction because it honors three directions that represent subsets necessary within addition of two values of a power. The model graphs valuation effects on shell-set values according to their placement within particular, implicated, orders-of-accumulation.1
Figure 5. Path choices in three directions, each direction 'taken' once, in order to accumulate any order of a + x + u, or, c total, number of shells.
Figure 6. Diagrammed number of shells based upon the logic in Figure 5, with shell-set values also indicated, accumulate to a c-shell total which is also a cn total value. All six significantly possible orders of occurrence are shown--all of which must be true statements if the commutative law of addition is honored.
The sketches in figure 6 depict shells in any possible order of occurrence of a, x and u numbers of shells regarding two terms that add up. Logically, shells must be considered in their first to last order. Shells are ordinal objects. So lengths within the diagram have two simultaneously applicable categories of name: 1) the number of shells which is an amount known from first to last; and/or, 2) a value of shells that a diagrammed length represents--specific portions of specific shell series for the specified power. Order of occurrence affects values of shells. For both categories, the summing of legs determine "hypotenuse" "lengths/values".
By the time that the vector that is logical travel from {0,0,0} to {a,x,u} is computed, the catecorner length that is central within the 3D diagram depicts a + x + u = c number of shells or sets of shell values that sum up to a cn value, diagramming all six significantly possible orders and computations of shell sets.
!!!But triangles in this model also correctly solve according to the right-angle rules of the Pythagorean Theorem--if shell-value lengths are treated as if they are already-squared roots. So square root values of shell values sets for any power are demonstrating the Pythagorean Theorem!!!
Thus, figures 5 and 6 simultaneously and correctly depict both non-Pythagorean and Pythagorean logic where additive depictions, in translation, should also adhere to the Pythagorean rules for right angled triangles where squared sides add up to the hypotenuse.
The Pythagorean Theorem by one of its proofs
The Pythagorean Theorem is provably true. Simon Singh gives one proof in his Appendix 1, page 287, of Fermat's Enigma:
Figure 7. A proof of the Pythagorean Theorem.
Figure 8. Application of the Pythagorean Theorem for right angles to values of a-, x- and u- shells sets in Figure 6 (which are based on an assumption that: an + bn = cn is possible). On the left, the diagram from the Pythagorean Theorem proof of Figure 7 is given. On the right is the application of the the logic of the shell-sets of Figures 5 and 6--which applies to all power levels--as participants subject to the Pythagorean Theorem.
If an + bn = cn is assumed possible, then shell-set values as diagrammed in Figure 6 will have to obey the Pythagorean Theorem by the square roots of three complete shell-set values as well as the square root of their total. So Sqrt an, Sqrt bn, Sqrt cn must evaluate as a Pythagorean Triple. The following equations which were established in the proof for the Pythagorean Theorem are reinterpreted more comprehensively:
Figure 9a. (a + b)2 = c2 + 2ab restates as: (Sqrt an + Sqrt bn)2 = (Sqrt cn)2 + 2(Sqrt an)(Sqrt bn)
Figure 9b. a2 + b2 = c2 restates as: (Sqrt an)2 + (Sqrt bn)2 = (Sqrt cn)2
Notice: If n = 1, then simply: a + b = c. If n = 2, then a, b, and c, are Pythagorean Triples and give the theorem as it is commonly known.
Figure 9c. Also apparent in Figure 6: 2a2 + (b2 - a2) = c2 (a value and u value [which are the same] plus x value = total) restates as: 2(Sqrt an)2 + (Sqrt (bn - an))2 = (Sqrt cn)2
So what happens if n is larger than 2?
Since the square roots of each of an and bn are "lengths" that will add up, after squared, to the "length" that is the square-root-of-cn-when-squared (according to the Pythagorean Theorem), these lengths in terms of an p, q, and r that are p2 and q2 that add up to r2 are, [the square root of an]= p, [the square root of bn]= q, and [the square root of cn] = r. But if the three values are Pythagorean Triples then:
Figure 10. From Dr. Math: Thus the formulas that give all Pythagorean triples are these: p = d*(m^2 - n^2), q = 2*d*m*n, r = d*(m^2 + n^2), where d is any positive integer, m > n > 0 are integers of opposite parity and relatively prime. . . . If you are given a triple p, q, and r, you can find d, m, and n in the following way. First of all, d = GCD(p,r). Then m = Sqrt[(r+p)/(2*d)] and n = Sqrt[(r-p)/(2*d)]. But follow-through shows contradictions! an and cn must both be squares so their roots are integers and have a Greatest Common Denominator d is at least 1 d = GCD (an/2, cn/2) as well as d = GCD (p, r) m = Sqrt [(cn/2 + an/2)/(2*d)] as well as m = Sqrt [(r + p)/(2*d)] n = Sqrt [(cn/2 - an/2)/(2*d)] as well as n = Sqrt [(r - p)/(2*d)] cn ± an must be divisible by 2d when summed (with either positive or negative an) AND the two versions of summands must both be squares for integer m and n. c and a must be of the same parity to be divisible by at least 2 for integer m and n. p = d * ((Sqrt [(cn/2 + an/2)/(2*d)])2 - (Sqrt [(cn/2 - an/2)/(2*d)])2) = Sqrt an r = d * ((Sqrt [(cn/2 + an/2)/(2*d)])2 + (Sqrt [(cn/2 - an/2)/(2*d)])2) = Sqrt cn q = d * (Sqrt [(cn/2 + an/2)/(2*d)]) * (Sqrt [(cn/2 - an/2)/(2*d)]) = Sqrt bn
Also note: square roots of each of a, b, and c do function when n = 1, because the square roots square to the values of a, b, and c, and the accumulation is simply linear.
For (Sqrt an)2 + (Sqrt bn)2 = (Sqrt cn)2 that must describe an + bn = cn, if it is true, there is no possible integer solution when n > 2.
The Pythagorean Theorem limits the Pythagorean Theorem
due to the commutative law of addition and the fact that shells/nexus numbers always sum to a cn value. Shells establish functioning subsets that do not allow cn to be divisible into "two powers of the same denomination" when the power level is greater than 2.
Cubum autem in duos cubos, aut quadrato-quadratum in duos quadrato-quadratos, et generaliter nullam in infinitum ultra quadratum potestatem in duos eiusdem nominis fas est dividere: cuius rei demonstrationem mirabilem sane detexi. Hanc marginis exiguitas non caperet. To divide a cube into two other cubes, a fourth power or in general any power whatever into two powers of the same denomination above the second is impossible, and I have discovered a truly marvelous demonstration of this proposition that this margin is too narrow to contain. --Pierre de Fermat
Regards, Cecilia October 1, 2005 1 Incidentally, this type of model holds for any number of examined subsets when order matters to the counted amounts within sets, and when choices are cumulative to one single, largest set. Values of Pascal's Triangle row z [do not count the top "1" of the triangle] also called C(z,0 to z-1) always enumerate the number of possible results at each of the 0th through (z-1)th choice. There are always z! possible paths going from no sets to all sets. There are always 2z possible subsets of z sets within the total, if you include 'no shells' as a subset. Finally, path diagrams look like sketches of z-dimensions.] |
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